Hi LawProgrammer,
In example below, the button does not get the new content and set for label1
<%@ Page Language="C#" %>
<%@ Register Namespace="CuteEditor" Assembly="CuteEditor" TagPrefix="CE" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<script runat="server">
protected override void OnLoad(EventArgs e)
{
editor1.Text = "I am label1";
label1.Text = editor1.Text;
base.OnLoad(e);
}
protected void btn_change_Click(object sender, EventArgs e)
{
label1.Text = editor1.Text;
}
</script>
<html xmlns="http://www.w3.org/1999/xhtml">
<head id="Head1" runat="server">
<title>Untitled Page</title>
</head>
<body>
<form id="form1" runat="server">
<div>
<CE:Editor ID="editor1" runat="server">
</CE:Editor>
<asp:Button ID="btn_change" runat="server" Text="Get editor text" OnClick="btn_change_Click" />
<asp:Label ID="label1" runat="server"></asp:Label>
</div>
</form>
</body>
</html>
And in the example below, the button get and set the new content correct.
<%@ Page Language="C#" %>
<%@ Register Namespace="CuteEditor" Assembly="CuteEditor" TagPrefix="CE" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<script runat="server">
protected override void OnLoad(EventArgs e)
{
if (!IsPostBack)
{
editor1.Text = "I am label1";
label1.Text = editor1.Text;
}
base.OnLoad(e);
}
protected void btn_change_Click(object sender, EventArgs e)
{
label1.Text = editor1.Text;
}
</script>
<html xmlns="http://www.w3.org/1999/xhtml">
<head id="Head1" runat="server">
<title>Untitled Page</title>
</head>
<body>
<form id="form1" runat="server">
<div>
<CE:Editor ID="editor1" runat="server">
</CE:Editor>
<asp:Button ID="btn_change" runat="server" Text="Get editor text" OnClick="btn_change_Click" />
<asp:Label ID="label1" runat="server"></asp:Label>
</div>
</form>
</body>
</html>
Please use the same way on your site. If you still can not get it work, please create an example page which can reproduce this issue and post here, I will check it and get back to you as soon as possible.
Regards,
Ken